He 0.010 mol effuse 1.25 min C2H6

He 0.010 mol effuse 1.25 min C2H6

 

 

If it takes 1.25 min for 0.010 moles of He to effuse,

how long will it take for the same amount of ethane, C2H6 to effuse?

 

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v1 / v2 = [M2 / M1]^(1/2)

( 참고 https://ywpop.tistory.com/3478 )

 

 

 

v = S / t 이므로,

t1 / t2 = [M1 / M2]^(1/2)

 

 

 

> He의 몰질량 = 4 g/mol

> C2H6의 몰질량 = 30 g/mol

 

 

 

t2 = t1 / [M1 / M2]^(1/2)

= 1.25 / [4 / 30]^(1/2)

= 3.42 min