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화학/원소(연소)분석

2.144 g sample 0.260 g C 0.347 g O 1.537 g Cl

by 영원파란 2021. 4. 21.

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2.144 g sample 0.260 g C 0.347 g O 1.537 g Cl

 

 

A 2.144 g sample of phosgene,

a compound used as a chemical warfare agent during World War I,

contains 0.260 g of carbon, 0.347 g of oxygen, and 1.537 g of chlorine.

What is the empirical formula of this substance?

 

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▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ]

▶ 참고: CH 연소분석 [ https://ywpop.tistory.com/9606 ]

 

 

 

각 성분의 몰수를 계산하면,

> 0.260 g / (12 g/mol) = 0.0217 mol C

( 참고 https://ywpop.tistory.com/7738 )

 

> 0.347 / 16 = 0.0217 mol O

> 1.537 / 35.45 = 0.0434 mol Cl

 

 

 

몰수의 가장 작은 정수비를 계산하면,

C : O : Cl = 0.0217 : 0.0217 : 0.0434

= 0.0217/0.0217 : 0.0217/0.0217 : 0.0434/0.0217

= 1 : 1 : 2

---> 실험식 = COCl2

 

 

 

 

[키워드] 포스겐 기준문서, 포스젠 기준문서

 

 

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