ΔE = q + w. 125 kJ heat 104 kJ work. 213 kJ heat ΔE –45 kJ

ΔE = q + w. 125 kJ heat 104 kJ work. 213 kJ heat ΔE –45 kJ

 

 

1) 어떤 계가 125 kJ의 열을 방출하고,

104 kJ의 일이 계에 행해졌을 때, ΔE는?

A system releases 125 kJ of heat

while 104 kJ of work is done on the system.

Calculate the change in internal energy.

 

2) 213 kJ의 열을 방출한 계의 ΔE가 –45 kJ.

이 계에 행한 일은?

A system releases 213 kJ of heat

and has a calculated ΔE of –45 kJ.

How much work was done on the system?

 

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1)

ΔE = q + w

( 참고 https://ywpop.tistory.com/5134 )

 

= (-125) + (+104)

= -21 kJ

 

 

 

 

2)

ΔE = q + w

-45 = (-213) + (w)

 

w = 213 - 45

= +168 kJ