10 mL unknown CuSO4 + 8.5 mL 0.02 N EDTA (f = 1.00)

10 mL unknown CuSO4 + 8.5 mL 0.02 N EDTA (f = 1.00)

 

 

10 mL unknown CuSO4 reacts with 8.5 mL 0.02 N EDTA (f = 1.00).

Calculate the concentration in mol/L.

 

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EDTA의 당량

= NVF = (0.02 eq/L) (8.5/1000 L) (1.00)

= 0.00017 eq

( 참고: factor, f https://ywpop.tistory.com/6123 )

 

 

 

CuSO4의 노르말농도

= 0.00017 eq / (10/1000 L)

= 0.017 eq/L

= 0.017 N

( 참고 https://ywpop.tistory.com/6131 )

 

 

 

CuSO4의 당량수 = 2 eq/mol 이므로,

( 참고 https://ywpop.tistory.com/4105 )

 

(0.017 eq/L) (1 mol / 2 eq) = 0.0085 mol/L