5.57 g Ag2O 75.0 mL tube 760 torr N2 28℃

5.57 g Ag2O 75.0 mL tube 760 torr N2 28℃

 

 

If 5.57 g of Ag2O is sealed in a 75.0 mL tube

filled with 760 torr of N2 gas at 28℃,

and the tube is heated to 310℃,

the Ag2O decomposes to form oxygen and silver.

What is the total pressure inside the tube

assuming the volume of the tube remains constant?

 

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전체 압력 = N2의 분압 + O2의 분압

Total pressure = partial pressure of N2 + partial pressure of O2

 

 

 

P / T = P’ / T’

( 참고 https://ywpop.tistory.com/7091 )

 

P’ = PT’ / T

= (1) (273.15+310) / (273.15+28)

= 1.936 atm N2

 

 

 

Ag2O의 몰질량 = 231.74 g/mol

5.57 g / (231.74 g/mol) = 0.02404 mol Ag2O

 

2Ag2O(s) → 4Ag(s) + O2(g)

 

0.02404 mol / 2 = 0.01202 mol O2

 

 

 

PV = nRT

( 참고 https://ywpop.tistory.com/3097 )

 

P = nRT / V

= (0.01202) (0.08206) (273.15+310) / (75.0/1000)

= 7.669 atm O2

 

 

 

전체 압력 = 1.936 + 7.669 = 9.605 atm

 

 

 

답: 9.61 atm

 

 

 

 

[키워드] 28℃ N2 gas 760 torr 75.0 mL 5.57 g Ag2O 310℃ total pressure