soluble compound XY2 dissociates in water

soluble compound XY2 dissociates in water

 

 

XY2(aq) ⇌ X^2+(aq) + 2Y^-(aq)

A soluble compound XY2 dissociates in water according to the equation above. In a 0.050 m solution of the compound, the XY2(aq) species is 40.0 percent dissociated. In the solution, the number of moles of particles of solute per 1.0 kg of water is closest to ( ).

 

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해리 전, XY2의 몰수를 계산하면,

(0.050 mol/kg) × (1.0 kg) = 0.050 mol XY2

 

 

XY2가 40.0% 해리되므로, 해리된 XY2의 몰수를 계산하면,

0.050 mol XY2 × 0.400 = 0.020 mol XY2

 

XY2 1몰당 3몰의 이온이 생성되므로,

생성된 이온의 몰수를 계산하면,

3 × 0.020 mol = 0.060 mol ions

 

 

해리되지 않은, 즉 남아있는 XY2의 몰수를 계산하면,

0.050 – 0.020 = 0.030 mol XY2

 

 

따라서 전체 용질 입자의 몰수는

0.060 mol + 0.030 mol = 0.090 mol

 

 

답: 0.090