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How many Br atoms are in 3.27 mol of SrBr2?

by 영원파란 2017. 2. 13.

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How many Br atoms are in 3.27 mol of SrBr2?

 

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(3.27 mol SrBr2) × (6.02×10^23 SrBr2 / 1 mol SrBr2) × (2Br / 1SrBr2)

= 3.94×10^24 Br

 

 

: 3.94×10^24

 

 

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