290 K H2 14.2 g Ar 36.7 g mixture 100.0 L

290 K H2 14.2 g Ar 36.7 g mixture 100.0 L

 

 

A mixture of 14.2 g of H2 and 36.7 g of Ar

is placed in a 100.0 L container at 290 K.

a) What is the partial pressure of H2 in atmospheres?

b) What is the partial pressure of Ar in atmosphere?

 

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▶ 참고: 돌턴의 분압법칙

[ https://ywpop.tistory.com/48 ]

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PV = nRT = (W/M)RT

( 참고 https://ywpop.tistory.com/3097 )

( 참고: n=W/M https://ywpop.tistory.com/7738 )

 

 

 

a)

P = (W/M)RT / V

= (14.2 / 2.02) (0.08206) (290) / (100.0)

= 1.67 atm

 

 

 

b)

P = (W/M)RT / V

= (36.7 / 39.95) (0.08206) (290) / (100.0)

= 0.219 atm