1 g Ca3P2는 2 g PH3를 생성

1 g Ca3P2는 2 g PH3를 생성

 

 

1 g Ca3P2는 2 g PH3를 생성한다.

Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3

one gram of Ca3P2 produces 2 g of PH3

 

 

Phosphine (PH3) can be prepared

by the reaction of calcium phosphide, Ca3P2:

Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3

Based on this equation,

which of the following statements are correct?

Show evidence to support your answer.

a) One mole of Ca3P2 produces 2 mol of PH3.

b) One gram of Ca3P2 produces 2 g of PH3.

c) Three moles of Ca(OH)2 are produced

for each 2 mol of PH3 produced.

d) The mole ratio between phosphine and

calcium phosphide is 2 mol PH3 over 1 mol Ca3P2.

 

---------------------------------------------------

 

> Ca3P2의 몰질량 = 182.18 g/mol

> PH3의 몰질량 = 34.00 g/mol

 

 

 

Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3

 

질량이 주어졌고, 질량을 요구했으므로,

질량비로 계산하면,

( 참고: 질량비로 계산 https://ywpop.tistory.com/5078 )

 

Ca3P2 : 2PH3 = 182.18 : 2(34.00) = 1 g : ? g

 

? = 2(34.00) / 182.18 = 0.37 g PH3

 

 

 

답: 0.37 g

 

 

 

 

[키워드] 1 g Ca3P2 2 g PH3 Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3