16 mol O2 반응 시 12 mol HCN 생성

16 mol O2 반응 시 12 mol HCN 생성

 

 

16 mol O2가 반응할 때마다 12 mol HCN이 생성된다.

2CH4 + 3O2 + 2NH3 → 2HCN + 6H2O

 

 

The equation representing the reaction used for

the commercial preparation of hydrogen cyanide is

2CH4 + 3O2 + 2NH3 → 2HCN + 6H2O

Based on this equation,

which of the following statements are correct?

Rewrite incorrect statements to make them correct.

a) Three moles of O2 are required for 2 mol of NH3.

b) Twelve moles of HCN are produced

for every 16 mol of O2 that react.

c) The mole ratio between H2O and CH4 is

6 mol H2O / 2 mol CH4

d) When 12 mol of HCN are produced,

4 mol of H2O will be formed.

e) When 10 mol of CH4, 10 mol of O2, and 10 mol of NH3

are mixed and reacted, O2 is the limiting reactant.

f) When 3 mol each of CH4, O2, and NH3

are mixed and reacted, 3 mol of HCN will be produced.

 

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2CH4 + 3O2 + 2NH3 → 2HCN + 6H2O

 

O2 : HCN = 3 : 2 계수비(= 몰수비) 이므로,

16 mol O2 반응 시,

생성되는 HCN의 몰수를 계산하면,

O2 : HCN = 3 : 2 = 16 mol : ? mol

 

? = 2 × 16 / 3 = 10.67 mol HCN

 

 

 

답: 11 mol

 

 

 

 

[키워드] 16 mol O2 12 mol HCN 2CH4 + 3O2 + 2NH3 → 2HCN + 6H2O