1 g Ca3P2는 2 g PH3를 생성
1 g Ca3P2는 2 g PH3를 생성한다.
Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
one gram of Ca3P2 produces 2 g of PH3
Phosphine (PH3) can be prepared
by the reaction of calcium phosphide, Ca3P2:
Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
Based on this equation,
which of the following statements are correct?
Show evidence to support your answer.
a) One mole of Ca3P2 produces 2 mol of PH3.
b) One gram of Ca3P2 produces 2 g of PH3.
c) Three moles of Ca(OH)2 are produced
for each 2 mol of PH3 produced.
d) The mole ratio between phosphine and
calcium phosphide is 2 mol PH3 over 1 mol Ca3P2.
---------------------------------------------------
> Ca3P2의 몰질량 = 182.18 g/mol
> PH3의 몰질량 = 34.00 g/mol
Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
질량이 주어졌고, 질량을 요구했으므로,
질량비로 계산하면,
( 참고: 질량비로 계산 https://ywpop.tistory.com/5078 )
Ca3P2 : 2PH3 = 182.18 : 2(34.00) = 1 g : ? g
? = 2(34.00) / 182.18 = 0.37 g PH3
답: 0.37 g
[키워드] 1 g Ca3P2 2 g PH3 Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
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