0.30 M KMnO4 32.0 mL + 0.60 M KMnO4 15.0 mL

0.30 M KMnO4 32.0 mL + 0.60 M KMnO4 15.0 mL

 

 

Calculate the concentration of each ion

in the following solutions obtained by mixing:

a) 32.0 mL of 0.30 M KMnO4 with 15.0 mL of 0.60 M KMnO4

Assume that the volumes are additive.

 

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(0.30 mol/L) (32.0/1000 L) = 0.0096 mol KMnO4

( 참고 https://ywpop.tistory.com/7787 )

 

(0.60 mol/L) (15.0/1000 L) = 0.009 mol KMnO4

 

 

 

혼합 용액의 몰농도 = 용질 mol수 / 용액 L수

= (0.0096 + 0.009 mol) / [(32.0 + 15.0)/1000 L]

= 0.396 M

 

 

 

KMnO4(aq) → K^+(aq) + MnO4^-(aq)

KMnO4 : K^+ : MnO4^- = 1 : 1 : 1 계수비(= 몰수비) 이므로,

[KMnO4] = [K^+] = [MnO4^-] = 0.396 M