15.0 g 에탄올의 연소열

15.0 g 에탄올의 연소열

 

 

If ethanol (15.0 g) is burned,

how much heat is released? Ethanol MW = 46.0 g/mol

C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) ... ΔH = –555 kJ

 

 

The complete combustion of ethanol,

C2H5OH (FW = 46.0 g/mol), proceeds as follows:

C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) ... ΔH = –555 kJ

What is the enthalpy change for

combustion of 15.0 g of ethanol?

(a) –12.1 kJ

(b) –181 kJ

(c) –422 kJ

(d) –555 kJ

(e) –1700 kJ

 

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C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) ... ΔH = –555 kJ

---> C2H5OH 1 mol당 연소열 = –555 kJ

---> C2H5OH의 연소열 = –555 kJ/mol

 

 

 

ΔH = –555 kJ/mol 이므로,

(15.0 g) (1 mol / 46.0 g) (–555 kJ/mol)

= (15.0) (1 / 46.0) (–555)

= –181 kJ

 

 

 

 

[키워드] 에탄올의 연소열 계산 기준문서, 에탄올의 연소열 기준문서, ethanol C2H5OH 46.0 g/mol ΔH = –555 kJ ethanol 15.0 g combustion