x M Fe^2+ 용액 100 mL + 0.1 M MnO4^- 용액 50 mL

x M Fe^2+ 용액 100 mL + 0.1 M MnO4^- 용액 50 mL

 

 

x M Fe^2+ 용액 100 mL 적정에

0.1 M MnO4^- 표준용액 50 mL가 소모되었다면,

x는?

 

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(0.1 mol/L) (50/1000 L) = 0.005 mol MnO4^-

( 참고 https://ywpop.tistory.com/7787 )

 

 

 

균형 맞춘 반응식

5Fe^2+ + MnO4^- + 8H^+ → 5Fe^3+ + Mn^2+ + 4H2O

( 참고 https://ywpop.tistory.com/7335 )

 

 

 

Fe^2+ : MnO4^- = 5 : 1 = ? mol : 0.005 mol

 

? = 5 × 0.005 = 0.025 mol Fe^2+

 

 

 

0.025 mol / (100/1000 L) = 0.25 mol/L

 

 

 

답: 0.25 M

 

 

 

 

[키워드] redox Fe^2+ + MnO4^-, redox MnO4^- + Fe^2+