sucrose 2.0 lb carbon water gram sucrose 25.2 g 0.994 g/mL

sucrose 2.0 lb carbon water gram sucrose 25.2 g 0.994 g/mL

 

 

In the presence of concentrated H2SO4, sucrose, C12H22O11,

undergoes dehydration, forming carbon and water:

C12H22O11 → 12C + 11H2O

a) How many grams of carbon and how many grams of water

can be produced from 2.0 lb of sucrose?

b) If 25.2 g sucrose is dehydrated,

how many grams of liquid water

with a density of 0.994 g/mL can be collected?

 

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> C12H22O11의 몰질량 = 342.30 g/mol

> C의 몰질량 = 12.01 g/mol

> H2O의 몰질량 = 18.02 g/mol

 

 

 

1 lb = 453.59237 g 이므로,

2.0 lb × (453.59237 g / 1 lb) = 907 g sucrose

 

 

 

a)

 

질량보존의 법칙에 따라,

질량비로 계산하면,

( 참고 https://ywpop.tistory.com/21578 )

 

C12H22O11 : 12C = 342.30 g : 12(12.01 g) = 907 g : ? g

 

? = [12(12.01) × 907] / 342.30 = 382 g C

 

 

 

C12H22O11 : 11H2O = 342.30 g : 11(18.02 g) = 907 g : ? g

 

? = [11(18.02) × 907] / 342.30 = 525 g H2O

 

 

 

b)

 

C12H22O11 : 11H2O = 342.30 g : 11(18.02 g) = 25.2 g : ? g

 

? = [11(18.02) × 25.2] / 342.30 = 14.6 g H2O

 

 

 

 

[참고] b)는 문제에 오타가 있는 것이 아닐까?

질량이 아니라 부피를 묻고 싶었던 것이 아닐까?

14.6 g / (0.994 g/mL) = 14.7 mL H2O