728x170
25.0 mL NaOH + 3.05 M HCl 5.2 mL
In a titration experiment, two drops of phenolphthalein
are added to 25.0 mL of aq. NaOH solution,
causing it to turn bright pink.
A solution of 3.05 M hydrochloric acid is added to the solution.
It is found that 5.2 mL of the acid solution
is required to turn the solution colorless.
What is the concentration of the original base solution?
---------------------------------------------------
HCl + NaOH → NaCl + H2O
M1V1 = M2V2
산의 몰수 = 염기의 몰수
( 참고 https://ywpop.tistory.com/4689 )
(3.05 M) (5.2 mL) = (? M) (25.0 mL)
? = (3.05) (5.2) / (25.0) = 0.6344 M
답: 0.634 M
[FAQ] [①23/06/11]
반응형
그리드형(광고전용)
'일반화학 > [16장] 산-염기 평형' 카테고리의 다른 글
| 짝산-짝염기. HCl + CH3OH ⇌ CH3OH2^+ + Cl^- (0) | 2022.06.09 |
|---|---|
| 산과 염기 구분. KOH + HF → KF + H2O (0) | 2022.06.09 |
| 지시약의 색. pH 3.0에서 리트머스 (0) | 2022.06.08 |
| 25.0 mL HNO3 + 1.50 M NaOH 28.3 mL (1) | 2022.06.08 |
| 0.042 M HBr 10.0 mL + 0.70 M NaOH 11.7 mL (1) | 2022.06.08 |
| 0.20 M HNO3 + 0.10 M C2H5NH2 100.0 mL. 당량점 pH (0) | 2022.06.06 |
| 0.1 M CH3COOH 100 mL + 0.1 M NaOH. 50.0 mL (0) | 2022.06.04 |
| 0.2 M HCOOH 용액의 pH (0) | 2022.06.04 |
댓글