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25.0 mL HNO3 + 1.50 M NaOH 28.3 mL
In a titration experiment, a solution of nitric acid is analyzed.
It is found that 28.3 mL of 1.50 M aqueous sodium hydroxide
is required to neutralize 25.0 mL of the nitric acid solution.
What is the molarity of the nitric acid solution?
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HNO3 + NaOH → NaNO3 + H2O
M1V1 = M2V2
산의 몰수 = 염기의 몰수
( 참고 https://ywpop.tistory.com/4689 )
(? M) (25.0 mL) = (1.50 M) (28.3 mL)
? = (1.50) (28.3) / (25.0) = 1.698 M
답: 1.70 M
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