[H2O(g)] = 7.9×10^(-2) M, [CO2(g)] = 0.93 M, [O2(g)] = 2.4×10^(-3) M

[H2O(g)] = 7.9×10^(-2) M, [CO2(g)] = 0.93 M, [O2(g)] = 2.4×10^(-3) M

 

 

The formation of glucose from water and carbon dioxide

is an extremely important reaction for life to exist.

Plants perform this reaction through the process of photosynthesis,

creating the base of the food chain. The unbalanced reaction is

H2O(g) + CO2(g) ⇌ C6H12O6(s) + O2(g)

 

At a particular temperature,

the following equilibrium concentrations were found:

[H2O(g)] = 7.9×10^(-2) M, [CO2(g)] = 0.93 M, [O2(g)] = 2.4×10^(-3) M.

Calculate the value of K at this temperature for the reaction

that produces 1 mol of glucose.

 

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균형 맞춘 반응식

6H2O(g) + 6CO2(g) ⇌ C6H12O6(s) + 6O2(g)

 

 

 

 

K = [O2]^6 / [H2O]^6 [CO2]^6

= ( [O2] / [H2O] [CO2] )^6

= ( (2.4×10^(-3)) / ((7.9×10^(-2)) (0.93)) )^6

= 1.2151×10^(-9)

 

 

 

답: 1.2×10^(-9)

 

 

 

 

[키워드] 6CO2(g) + 6H2O(g) ⇌ C6H12O6(s) + 6O2(g), 6CO2 + 6H2O ⇌ C6H12O6 + 6O2, CO2(g) + H2O(g) ⇌ C6H12O6(s) + O2(g), CO2 + H2O ⇌ C6H12O6 + O2