binding energy of Ti is 3.14×10^3 kJ/mol

binding energy of Ti is 3.14×10^3 kJ/mol

 

 

Determine the shortest frequency of light

required to remove an electron from a sample of Ti metal,

if the binding energy of titanium is 3.14×10^3 kJ/mol.

 

---------------------------------------------------

 

(3.14×10^3 kJ/mol) (1 mol / 6.022×10^23 개)

= (3.14×10^3) (1 / (6.022×10^23))

= 5.214×10^(-21) kJ

= 5.214×10^(-18) J

---> Ti metal 1개의 binding energy

 

 

 

E = hν = h(c/λ) = hc/λ

( 참고 https://ywpop.tistory.com/4964 )

 

ν = E / h

= (5.214×10^(-18) J) / (6.626×10^(-34) J•s)

= (5.214×10^(-18)) / (6.626×10^(-34))

= 7.87×10^15 /s

= 7.87×10^15 Hz

 

 

 

답: 7.87×10^15 Hz