561.2 J heat 8.00 g water final temp 64.2℃

561.2 J heat 8.00 g water final temp 64.2℃

 

 

561.2 J of heat was added to 8.00 g of water.

The final temperature of the water was measured to be 64.2℃.

What was the initial temperature of the water?

> specific heat capacity of water = 4.184 J/g•℃

 

---------------------------------------------------

 

q = C m Δt

( 참고 https://ywpop.tistory.com/2897 )

 

 

 

initial temperature = x 라 두면,

 

(561.2 J) = (4.184 J/g•℃) (8.00 g) (64.2 – x ℃)

 

64.2 – x = 561.2 / ((4.184) (8.00))

 

x = 64.2 – [561.2 / ((4.184) (8.00))] = 47.43

 

 

 

답: 47.4℃