What would be the temperature inside the pressure cooker

What would be the temperature inside the pressure cooker

 

 

What would be the temperature inside the pressure cooker

if the vapor pressure of water was 2.85 atm?

The enthalpy of vaporization of water is 40.7 kJ/mol.

 

---------------------------------------------------

 

> P_1 = 1 atm, T_1 = 273 + 100 = 373 K

( 물의 정상 끓는점 = 100℃ )

 

> P_2 = 2.85 atm, T_2 = ? K

 

 

 

Clausius-Clapeyron 식

ln(P1 / P2) = ΔH_vap/R (1/T2 – 1/T1)

( 참고 https://ywpop.tistory.com/3133 )

 

 

 

ln(1 / 2.85) = (40700 / 8.314) (1/T2 – 1/373)

 

1/T2 – 1/373 = ln(1 / 2.85) / (40700 / 8.314)

 

1/T2 = ln(1 / 2.85) / (40700 / 8.314) + 1/373

 

T2 = 1 / [ln(1 / 2.85) / (40700 / 8.314) + 1/373]

= 405.35 K

 

 

 

답: 405 K

( 405 – 273 = 132℃ )