0.250 mol H2O 60.0 g NO2 225 g NO2 55.2 g H2O gram HNO3

0.250 mol H2O 60.0 g NO2 225 g NO2 55.2 g H2O gram HNO3

 

 

When nitrogen dioxide (NO2) from car exhaust

combines with water in the air,

it forms nitric acid (HNO3),

which causes acid rain, and nitrogen oxide:

3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)

 

a) How many molecules of NO2 are needed

to react with 0.250 mol of H2O?

b) How many grams of HNO3 are produced

when 60.0 g of NO2 completly reacts?

c) How many grams of HNO3 can be produced

if 225 g of NO2 is mixed with 55.2 g of H2O?

 

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a)

NO2 : H2O = 3 : 1 = ? mol : 0.250 mol

? = 3 × 0.250 = 0.750 mol NO2

 

(0.750 mol) (6.022×10^23 개/mol) = 4.52×10^23 개 NO2

 

 

 

 

b)

NO2의 몰질량 = 46.01 g/mol 이므로,

60.0 g / (46.01 g/mol) = 1.304 mol NO2

( 참고 https://ywpop.tistory.com/7738 )

 

 

NO2 : HNO3 = 3 : 2 = 1.304 mol : ? mol

? = 2 × 1.304 / 3 = 0.869 mol HNO3

 

 

HNO3의 몰질량 = 63.01 g/mol 이므로,

0.869 mol × (63.01 g/mol) = 54.8 g HNO3

 

 

 

 

c)

> 225 / 46.01 = 4.89 mol NO2

> 55.2 / 18.015 = 3.064 mol H2O

 

 

NO2 : H2O = 3 : 1 = 4.89 mol : ? mol

? = 4.89 / 3 = 1.63 mol H2O

---> H2O는 이만큼 있다, 남는다?

---> H2O = 과잉 반응물, NO2 = 한계 반응물.

( 참고: 한계 반응물 https://ywpop.tistory.com/3318 )

 

 

NO2 : HNO3 = 3 : 2 = 4.89 mol : ? mol

? = 2 × 4.89 / 3 = 3.26 mol HNO3

 

 

3.26 × 63.01 = 205 g HNO3

 

 

 

 

[키워드] 3NO2(g) + H2O(l) → NO(g) + 2HNO3(aq)