300 K 40 mL O3(g) 100 g water 1.0 atm 400 g 4.0 atm

300 K 40 mL O3(g) 100 g water 1.0 atm 400 g 4.0 atm

 

 

At 300 K, 40 mL of O3(g) dissolves in 100 g of water at 1.0 atm.

What mass of ozone dissolved in 400 g of water

at a pressure of 4.0 atm at 300 K?

 

---------------------------------------------------

 

헨리의 법칙

S_g = kP_g

( 참고 https://ywpop.tistory.com/1911 )

 

 

 

 

 

S1 / P1 = S2 / P2

 

(40 mL / 100 g) / (1.0 atm) = (? mL / 400 g) / (4.0 atm)

 

(40 / 100) = (? / 400) / 4.0

 

? = (40 / 100) × 4.0 × 400 = 640 mL

 

 

 

PV = nRT

( 참고 https://ywpop.tistory.com/3097 )

 

n = PV / RT

= [(4.0) (0.640)] / [(0.08206) (300)]

= 0.10 mol

 

 

 

O3의 몰질량 = 48.00 g/mol 이므로,

0.10 mol × (48.00 g/mol) = 4.8 g O3

 

 

 

답: 4.8 g