HCl percent yield 75% 328 g HCl PCl3 mol

HCl percent yield 75% 328 g HCl PCl3 mol

 

 

다음 반응에서 HCl의 수득률이 75%였다면,

328 g의 HCl을 얻기위해 필요한 PCl3의 몰수는?

PCl3 + 3NH3 → P(NH2)3 + 3HCl

 

 

When the following reaction is run, a 75% yield is achieved:

PCl3(g) + 3NH3(g) → P(NH2)3(g) + 3HCl(g)

How many moles of phosphorous trichloride are required

to produce 328 g of HCl?

 

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HCl의 몰질량 = 36.46 g/mol

328 g / (36.46 g/mol) = 8.996 mol HCl

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

수득률이 75%이므로,

8.996 mol / (75/100) = 11.99 mol HCl

 

 

 

PCl3 : HCl = 1 : 3 계수비(= 몰수비) 이므로,

PCl3 : HCl = 1 : 3 = ? mol : 11.99 mol

? = 11.99 / 3 = 3.997 mol PCl3

 

 

 

답: 4.00 mol