HCl 13.7 g 0.500 L 18℃ osmo pressure

HCl 13.7 g 0.500 L 18℃ osmo pressure

 

 

What is the osmotic pressure of a solution

prepared from 13.7 g of the electrolyte HCl

and enough water to make 0.500 L of solution at 18℃?

 

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π = iMRT

( 참고 https://ywpop.tistory.com/1921 )

 

 

 

HCl(aq) → H^+(aq) + Cl^-(aq)

---> i = 2

 

 

 

HCl의 몰질량 = 36.46 g/mol

13.7 g / (36.46 g/mol) = 0.37575 mol HCl

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

몰농도 = 용질 mol수 / 용액 L수

= 0.37575 mol / 0.500 L

= 0.7515 M

 

 

 

π = iMRT

= (2) (0.7515) (0.08206) (273.15+18)

= 35.9 atm