C3H8 5.00 mol O2 gas 18.5 g C3H8 46.3 g

C3H8 5.00 mol O2 gas 18.5 g C3H8 46.3 g

 

 

Propane gas (C3H8) reacts with oxygen to produce carbon dioxide and water.

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

a. How many moles of H2O form when 5.00 moles of C3H8 completely reacts?

b. How many grams of CO2 are produced from 18.5 g of oxygen gas?

c. How many grams of H2O can be produced when 46.3 g of C3H8 reacts?

 

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a. How many moles of H2O form when 5.00 moles of C3H8 completely reacts?

 

C3H8 : H2O = 1 : 4 계수비(= 몰수비) 이므로,

C3H8 : H2O = 1 : 4 = 5.00 mol : ? mol

? = 4 × 5.00 = 20 mol H2O

 

 

 

 

b. How many grams of CO2 are produced from 18.5 g of oxygen gas?

 

O2의 몰질량 = 32.00 g/mol

18.5 g / (32.00 g/mol) = 18.5/32.00 mol O2

( 참고 https://ywpop.tistory.com/7738 )

 

 

O2 : CO2 = 5 : 3 = 18.5/32.00 mol : ? mol

? = 3 × (18.5/32.00) / 5 = 0.347 mol CO2

 

 

CO2의 몰질량 = 44.01 g/mol

0.347 mol × (44.01 g/mol) = 15.3 g CO2

 

 

 

 

c. How many grams of H2O can be produced when 46.3 g of C3H8 reacts?

 

C3H8의 몰질량 = 44.10 g/mol

46.3 g / (44.10 g/mol) = 46.3/44.10 mol C3H8

 

 

C3H8 : H2O = 1 : 4 = 46.3/44.10 mol : ? mol

? = 4 × (46.3/44.10) = 4.20 mol H2O

 

 

H2O의 몰질량 = 18.02 g/mol

4.20 mol × (18.02 g/mol) = 75.7 g H2O