35℃ 0.55 atm methane 250 mL 35℃ 1.5 atm propane 750 mL 10.0 L

35℃ 0.55 atm methane 250 mL 35℃ 1.5 atm propane 750 mL 10.0 L

 

 

250 mL of methane, CH4, at 35 °C and 0.55 atm

and 750 mL of propane, C3H8, at 35 °C and 1.5 atm,

were introduced into a 10.0 L container.

What is the final pressure, in torr, of the mixture?

 

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P1V1 = P2V2

( 참고 https://ywpop.tistory.com/1977 )

 

 

 

각 기체의 분압 (partial pressure)

> P2 = (0.55) (0.250) / (10.0) = 0.01375 atm CH4

> P2 = (1.5) (0.750) / (10.0) = 0.1125 atm C3H8

 

 

 

전체 압력 (total pressure)

P_tot = 0.01375 + 0.1125 = 0.12625 atm

 

 

 

 

또는

P1V1 + P2V2 = P3V3

(0.55) (0.250) + (1.5) (0.750) = P3 (10.0)

 

P3 = [(0.55) (0.250) + (1.5) (0.750)] / (10.0)

= 0.12625 atm

 

 

 

 

(0.12625 atm) (760 torr / 1 atm) = 95.95 torr

 

 

 

답: 96.0 torr

 

 

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250 mL of methane, CH4, at 35 °C and 0.55 atm

and 750 mL of propane, C3H8, at 35 °C and 1.5 atm,

were introduced into a 10.0 L container.

What is the mole fraction of methane in the mixture?

 

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PV = nRT

( 참고 https://ywpop.tistory.com/3097 )

 

 

n = PV / RT

= [(0.55) (0.250)] / [(0.08206) (273.15 + 35)]

= 0.00544 mol CH4

 

 

n = PV / RT

= [(1.5) (0.750)] / [(0.08206) (273.15 + 35)]

= 0.0445 mol C3H8

 

 

 

CH4의 몰분율을 계산하면,

0.00544 / (0.00544 + 0.0445)

= 0.1089

( 참고: 몰분율 https://ywpop.tistory.com/2659 )

 

 

 

답: 0.11

 

 

 

 

[키워드] P1V1 + P2V2 = P3V3 기준문서, P1V1 + P2V2 기준문서, P1V1 + P2V2 = P3V3 사전, P1V1 + P2V2 사전