gold foil thickness 0.0005 mm diameter 2.9×10^(-8) cm

gold foil thickness 0.0005 mm diameter 2.9×10^(-8) cm

 

 

러더퍼드 산란 실험에 사용한 금박은 두께가 0.0005 mm이다.

금 원자의 지름이 2.9×10^(-8) cm이면,

금박 두께에 몇 개의 원자가 있는가?

 

 

The gold foil that Rutherford used in his scattering experiment

had a thickness of approximately 0.0005 mm.

If a single gold atom has a diameter of 2.9×10^(-8) cm,

how many atoms thick was Rutherfords foil?

 

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[(0.0005 mm) (1 m / 1000 mm)] / [(2.9×10^(-8) cm) (1 m / 100 cm)]

= [(0.0005) (1 / 1000)] / [(2.9×10^(-8)) (1 / 100)]

= 1724

= 2×10^3 atoms