gold foil thickness 0.006 mm diameter 2.9×10^(-10) m

gold foil thickness 0.006 mm diameter 2.9×10^(-10) m

 

 

러더퍼드 산란 실험에 사용한 금박은 두께가 0.006 mm이다.

금 원자의 지름이 2.9×10^(-10) m이면,

금박 두께에 몇 개의 원자가 있는가?

 

 

The gold foil that Rutherford used in his scattering experiment

had a thickness of approximately 0.006 mm.

If a single gold atom has a diameter of 2.9×10^(-10) m,

how many atoms thick was Rutherfords foil?

 

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[(0.006 mm) (1 m / 1000 mm)] / (2.9×10^(-10) m)

= [(0.006) (1 / 1000)] / (2.9×10^(-10))

= 20690

= 2×10^4 atoms

 

 

 

 

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