0.93 g HCl 0.40 L pH

0.93 g HCl 0.40 L pH

 

 

0.93 g 염화수소를 물에 용해시켜 0.40 L로 만든 용액의 pH

 

 

Calculate the pH of solution prepared by:

b) Dissolving 0.93 g of hydrogen chloride in water

to give 0.40 L of solution

 

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HCl의 몰질량 = 36.46 g/mol

0.93 g / (36.46 g/mol) = 0.0255 mol HCl

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

몰농도 = 용질 mol수 / 용액 L수

= 0.0255 mol / 0.40 L

= 0.064 M

 

 

 

HCl은 강산, 100% 이온화된다고 가정하면,

HCl(aq) → H^+(aq) + Cl^-(aq)

[HCl] = [H^+] = 0.064 M

 

 

 

pH = -log[H^+]

= -log(0.064)

= 1.19