250.0 mL 포화 용액 중 KBT의 최대 질량

250.0 mL 포화 용액 중 KBT의 최대 질량

 

 

Cream of tartar, a common ingredient in cooking,

is the common name for potassium bitartrate

(abbreviated KBT, molar mass = 188.2 g/mol).

Historically, KBT was a crystalline solid

that formed on the casks of wine barrels

during the fermentation process.

Calculate the maximum mass of KBT

that can dissolve in 250.0 mL of solution

to make a saturated solution.

The Ksp value for KBT is 3.8×10^(-4).

 

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KBT(s) ⇌ K^+(aq) + BT^-(aq)

Ksp = [K^+] [BT^-]

 

 

 

KBT의 몰용해도를 s라 두면,

Ksp = [K^+] [BT^-]

3.8×10^(-4) = (s) (s)

( 참고 https://ywpop.tistory.com/8434 )

 

 

 

s^2 = 3.8×10^(-4)

 

s = [3.8×10^(-4)]^(1/2)

= 0.019 M

 

 

 

(0.019 mol/L) × (250.0/1000 L) = 0.00475 mol KBT

( 참고 https://ywpop.tistory.com/7787 )

 

 

 

0.00475 mol × (188.2 g/mol) = 0.89 g KBT

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

[키워드] 타르타르산 칼륨, 바이타르타르산 칼륨, 타르타르산 포타슘, 바이타르타르산 포타슘

KBT wine 250.0 mL Ksp 3.8×10^(-4) 188.2 g/mol

 

 

 

 

 

[그림] Potassium bitartrate의 구조식.

 

 

 

> s = [3.8×10^(-4)]^(1/2) = 0.0194936 M

> (0.0194936 mol/L) × (250.0/1000 L) = 0.0048734 mol KBT

> 0.0048734 mol × (188.2 g/mol) = 0.917 g KBT