0.3 M NaF 용액의 pH

0.3 M NaF 용액의 pH

(HF의 Ka = 7.1×10^(-4))

 

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▶ 참고: NaF 용액의 pH [ https://ywpop.tistory.com/4200 ]

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Kh = Kw / Ka

= (10^(-14)) / (7.1×10^(-4))

= 1.41×10^(–11)

 

 

 

Kh = x^2 / 0.3 = 1.41×10^(–11)

 

x = [(1.41×10^(–11)) × 0.3]^(1/2)

= 2.06×10^(-6) M = [OH^-]

 

 

 

pOH = -log[OH^-]

= -log(2.06×10^(-6)) = 5.69

 

pH = 14 – pOH

= 14 – 5.69 = 8.31

 

 

 

답: pH = 8.31