2.15% 50.0% 0.9984 g 2.07 wt% Ni 0.790 g/mL

2.15% 50.0% 0.9984 g 2.07 wt% Ni 0.790 g/mL

 

 

How many milliliters of 2.15% alcoholic dimethylglyoxime should be used to provide a 50.0% excess for Reaction 26-7 with 0.998 4 g of steel containing 2.07 wt% Ni? Assume that the density of the dimethylglyoxime solution is 0.790 g/mL.

 

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0.9984 g × (2.07/100) = 0.0206669 g Ni

 

 

Ni의 몰질량 = 58.69 g/mol 이므로,

0.0206669 g / (58.69 g/mol) = 0.000352137 mol Ni

 

 

Ni : DMG = 1 : 2 계수비(= 몰수비) 이므로,

0.000352137 mol Ni과 반응하는 DMG의 몰수

= 2 × 0.000352137 mol = 0.000704274 mol DMG

 

 

DMG의 몰질량 = 288.91 g/mol 이므로,

0.000704274 mol × (288.91 g/mol) = 0.203472 g DMG

 

 

DMG 용액의 순도가 2.15%이므로,

0.203472 g / (2.15/100) = 9.46381 g DMG 용액

 

 

DMG 용액을 50.0% 과량 첨가하므로,

9.46381 g / (50.0/100) = 18.9276 g DMG 용액(50% 과량)

 

 

질량을 부피로 환산하면,

18.9276 g / (0.790 g/mL) = 24.0 mL DMG 용액(50% 과량)