반응속도론. decomposition of dimethyl ether, (CH3)2O

반응속도론. decomposition of dimethyl ether, (CH3)2O

 

 

510℃에서 (CH3)2O의 분해 반응은 일차 반응으로서, 속도 상수는 6.8×10^-4 s^-1이다.

(CH3)2O(g) → CH4(g) + H2(g) + CO(g)

(CH3)2O의 초기 압력이 135 torr이면, 1420초 후 부분 압력은 얼마인가?

 

The decomposition of dimethyl ether, (CH3)2O, at 510°C is a first-order process with a rate constant of 6.8×10^-4 s^-1.

(CH3)2O(g) → CH4(g) + H2(g) + CO(g)

If the initial pressure of (CH3)2O is 135 torr, what is its partial pressure after 1420 s?

 

-----------------------------------------

 

ln[A]_t = -kt + ln[A]_0

 

 

[A]_0 = 135 torr

[A]_t = x

k = 6.8×10^-4 s^-1

t = 1420 s

 

 

ln[A]_t = -kt + ln[A]_0

ln(x) = -(6.8×10^-4) (1420) + ln(135)

ln(x) = -0.9656 + 4.9053

ln(x) = 3.9397

x = e^3.9397

x = 51.4 torr

 

 

답: 51.4 torr