ZnS 1.00 g을 태울 때 발생하는 열(kJ)

ZnS 1.00 g을 태울 때 발생하는 열(kJ)

 

 

ZnS 1.00 g을 태울 때 발생하는 열(kJ)을 계산하시오.

2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g) ... ΔH = -879 kJ/mol

(원자량: Zn=65.39, S=32.07, O=16.00)

 

The first step in the industrial recovery of zinc from the zinc sulfide ore is roasting, that is, the conversion of ZnS to ZnO by heating:

2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g) ... ΔH = -879 kJ/mol

Calculate the heat evolved (in kJ) when 1.00 g of ZnS is roasted.

Calculate the heat evolved (in kJ) per grams of ZnS roasted.

 

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ZnS의 1.00 g의 몰수를 계산하면,

1.00 g / (65.39+32.07 g/mol) = 0.01026062 mol

 

ZnS 2몰당 -879 kJ 이므로,

2 : -879 = 0.01026062 : ?

? = -879 × 0.01026062 / 2 = -4.50954249

 

 

답: -4.51 kJ