37℃ 101.33 kPa 10.0 g C6H12O6 CO2 vol 100 kPa 298 K 15.0 g glucose O2 vol

37℃ 101.33 kPa 10.0 g C6H12O6 CO2 vol 100 kPa 298 K 15.0 g glucose O2 vol

 

 

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas:

C6H12O6(aq) + 6O2(g) → 6CO2(g) + 6H2O(l)

a) Calculate the volume of dry CO2 produced at normal body temperature, 37℃, and 101.33 kPa when 10.0 g of glucose is consumed in this reaction.

b) Calculate the volume of oxygen you would need, at 100 kPa and 298 K, to completely oxidize 15.0 g of glucose.

 

 

우리 몸에서는 글루코스(C6H12O6)의 대사 산화를 통해

CO2를 생산하여 폐에서 기체로 방출한다.

C6H12O6(aq) + 6O2(g) → 6CO2(g) + 6H2O(l)

a) 37℃, 101.33 kPa에서 10.0 g의 글루코스가 위 반응에서

소모될 때, 생성되는 건조한 CO2의 부피를 계산하시오.

b) 100 kPa, 298 K에서 15.0 g의 글루코스를 완전히

산화시키기 위해 필요한 산소의 부피를 계산하시오.

 

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답:

a) 8.476 L CO2

b) 12.38 L O2

[ https://ywpop.blogspot.com/2024/05/37-10133-kpa-100-g-c6h12o6-co2-vol-100.html ]

 

 

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37℃ 0.970 atm 24.5 g C6H12O6 CO2 vol 1.00 atm 298 K 50.0 g glucose O2 vol

 

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas:

C6H12O6(aq) + 6O2(g) → 6CO2(g) + 6H2O(l)

 

a) Calculate the volume of dry CO2 produced at body temperature (37℃) and 0.970 atm when 24.5 g of glucose is consumed in this reaction.

답: 21.41 L CO2

 

b) Calculate the volume of oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 50.0 g of glucose.

답: 40.72 L O2

 

 

 

[키워드] 글루코스 화학량론 기준, glucose 화학량론 기준, C6H12O6 화학량론 기준