728x170
Al 42.7 g 15.2℃ heat energy
What quantity of heat energy must have been applied
to a block of aluminum weighing 42.7 g,
if the temperature of the block of aluminum increased by 15.2℃?
The specific heat of aluminum is 0.89 J/g•℃.
---------------------------------------------------
▶ 참고: 열용량과 비열
[ https://ywpop.tistory.com/2897 ]
---------------------------------------------------
q = C m Δt
= (0.89 J/g•℃) (42.7 g) (15.2 ℃)
= (0.89) (42.7) (15.2)
= 578 J
답: 578 J
반응형
그리드형(광고전용)
'일반화학 > [05장] 열화학' 카테고리의 다른 글
| 생성엔탈피로 반응엔탈피 계산. CH4(g) 불완전 연소열 (1) | 2023.06.16 |
|---|---|
| ΔE 계산. 1.90 atm 8.30 L 2.80 L 350.0 J heat internal energy (0) | 2023.06.14 |
| gold 55.5 g temp 20℃ 45℃ increase heat (3) | 2023.06.11 |
| Hg 25 g 100. J heat energy temp increase (1) | 2023.06.11 |
| –30.℃ 얼음 1.00 mol을 140.℃ 수증기로 (kJ) (3) | 2023.06.11 |
| 생성엔탈피로 반응엔탈피 계산. CuO 연소열 (1) | 2023.06.11 |
| 중화열 계산. 0.500 M HCl + 0.500 M NaOH 1.00×10^2 mL (3) | 2023.06.10 |
| ΔH° = –484 kJ 0.25 mol O2 0.50 mol H2 –5.6 L PV work ΔE (4) | 2023.06.09 |
댓글