testosterone C19H28O2 3.88×10^21 H atoms

testosterone C19H28O2 3.88×10^21 H atoms

 

 

A sample of the male sex hormone testosterone,

C19H28O2, contains 3.88×10^21 hydrogen atoms.

(a) How many atoms of carbon does it contain?

(b) How many molecules of testosterone does it contain?

(c) How many moles of testosterone does it contain?

(d) What is the mass of this sample in grams?

 

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(a) How many atoms of carbon does it contain?

 

1개 C19H28O2 분자 속에

19개 탄소 원자와 28개 수소 원자가 들어있으므로,

C : H = 19 : 28 = ? : 3.88×10^21

 

? = 19 × (3.88×10^21) / 28 = 2.63×10^21 C atoms

 

 

 

(b) How many molecules of testosterone does it contain?

 

C19H28O2 : H = 1 : 28 = ? : 3.88×10^21

 

? = (3.88×10^21) / 28 = 1.39×10^20 molecules

 

 

 

(c) How many moles of testosterone does it contain?

 

1 mol = 6.022×10^23 개 이므로,

(1.39×10^20 개) (1 mol / (6.022×10^23 개))

= (1.39×10^20) (1 / (6.022×10^23))

= 2.31×10^(-4) mol

 

 

 

(d) What is the mass of this sample in grams?

 

C19H28O2의 몰질량

= 19(12) + 28(1) + 2(16) = 288 g/mol 이므로,

 

(2.31×10^(-4) mol) (288 g/mol) = 0.0665 g

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

 

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