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balloon 1.30 L air 24.7℃ nitrogen –78.5℃ volume

by 영원파란 2023. 3. 28.

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balloon 1.30 L air 24.7℃ nitrogen –78.5℃ volume

 

 

Suppose a balloon containing 1.30 L of air at 24.7℃

is placed into a beaker containing liquid nitrogen at –78.5℃.

What will the volume of the sample of air become (at constant pressure)?

 

---------------------------------------------------

 

V1 / T1 = V2 / T2

( 참고 https://ywpop.tistory.com/1978 )

 

 

 

V2 = V1T2 / T1

= (1.30 × (273.15 – 78.5)) / (273.15 + 24.7)

= 0.8496 L

 

 

 

답: 0.850 L

 

 

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