10 lb A (SG 0.879) 20 lb B (SG 0.866) 혼합물

10 lb A (SG 0.879) 20 lb B (SG 0.866) 혼합물

 

 

10 lb의 A (SG 0.879, MW 78),

20 lb의 B (SG 0.866, MW 92) 의 혼합물에서,

(1) 이 혼합물의 부피 (ft3)

(2) 혼합물 10 mL 속 B의 질량 (g)

 

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▶ 참고: 질량 환산 [ https://ywpop.tistory.com/22440 ]

▶ 참고: 부피 환산 [ https://ywpop.tistory.com/17461 ]

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A의 밀도 = 0.879 g/mL 단위를 lb/ft3 단위로 환산하면,

 

(0.879 g/mL) (1 lb / 453.59237 g) (1000 mL / 1 L) (1000 L / 1 m3) (0.3048^3 m3 / 1 ft3)

= (0.879) (1 / 453.59237) (1000) (1000) (0.3048^3)

= 54.8742 lb/ft3

 

 

 

B의 밀도 = 0.866 g/mL

 

(0.866) (1 / 453.59237) (1000) (1000) (0.3048^3)

= 54.0626 lb/ft3

 

 

 

10 lb × (1 ft3 / 54.8742 lb) + 20 lb × (1 ft3 / 54.0626 lb)

= 10 × (1 / 54.8742) + 20 × (1 / 54.0626)

= 0.552 ft3

---> (1) 이 혼합물의 부피 (ft3)

 

 

 

 

(0.552 ft3) (0.3048^3 m3 / 1 ft3) (1000 L / 1 m3) (1000 mL / 1 L)

= (0.552) (0.3048^3) (1000) (1000)

= 15630.8993 mL

 

 

 

15630.8993 mL : 20 lb = 10 mL : ? lb

 

? = 20 × 10 / 15630.8993 = 0.012795 lb

 

 

 

0.012795 lb × (453.59237 g / 1 lb) = 5.8037 g

---> (2) 혼합물 10 mL 속 B의 질량 (g)

 

 

 

 

[키워드]

10 pounds of benzene (SG = 0.879) and

Ten pounds of benzene (SG = 0.879) and

20 pounds of toluene (SG = 0.866) are mixed.

Calculate the following properties of the final mixture

assuming that the mixture volume is

the sum of the individual component volumes.

a) Mass fraction of benzene and toluene

b) Mole fraction of benzene and toluene

c) Mass ratio of toluene and benzene (kgT/kgB)

d) Volume

e) Density and specific volume

f) Concentration of toluene (Ibmoles/ft3)

g) Molarity of toluene

h) Mass of toluene in 10 mL of the mixture