0.251 M HCl 125 mL + water 250.0 mL

0.251 M HCl 125 mL + water 250.0 mL

 

 

물 250.0 mL 가했을 때 새로운 몰농도 계산

0.251 M HCl 125 mL

 

 

Calculate the new molarity that results

when 250. mL of water is added

to each of the following solutions.

a. 125 mL of 0.251 M HCl

b. 445 mL of 0.499 M H2SO4

c. 5.25 L of 0.101 M HNO3

d. 11.2 mL of 14.5 M HC2H3O2

 

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묽힘법칙

M1V1 = M2V2

( 참고 https://ywpop.tistory.com/2859 )

 

 

 

(0.251 M) (125 mL) = (? M) (125+250.0 mL)

 

? = (0.251) (125) / (125+250.0) = 0.0837 M

 

 

 

답: 0.0837 M

 

 

 

 

[참고] 나머지 문제도

부피 단위만 신경써서(통일시켜)

묽힘법칙 공식에 대입해서 계산하면 됩니다.

 

 

 

c. 5.25 L of 0.101 M HNO3

(0.101 M) (5.25 L) = (? M) (5.25+(250.0/1000) L)

? = (0.101) (5.25) / (5.25+(250.0/1000)) = 0.0964 M