water boil 74 kJ heat 2.3×10^(-3) m mol photon

water boil 74 kJ heat 2.3×10^(-3) m mol photon

 

 

74 kJ are required to heat 1 cup of water from room temperature to boiling.

The wavelength of microwave radiation in a microwave oven

is 2.3×10^(-3) m. How many moles of photons are required?

 

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E = hν = h(c/λ) = hc/λ

( 참고 https://ywpop.tistory.com/4964 )

 

= [(6.626×10^(-34) J•s) (2.998×10^8 m/s)] / (2.3×10^(-3) m)

= [(6.626×10^(-34)) (2.998×10^8)] / (2.3×10^(-3))

= 8.637×10^(-23) J

---> 광자 1개의 에너지

 

 

 

74000 J / (8.637×10^(-23) J/개)

= 74000 / (8.637×10^(-23))

= 8.568×10^26 개 광자

 

 

 

(8.568×10^26 개) (1 mol / (6.022×10^23 개))

= (8.568×10^26) (1 / (6.022×10^23))

= 1423 mol

 

 

 

답: 1.4×10^3 mol

 

 

 

 

[키워드] 전자레인지 기준문서, microwave oven dic