ore 0.456 g Cr 0.560 mg Cr2O3 % ppt ppm

ore 0.456 g Cr 0.560 mg Cr2O3 % ppt ppm

 

 

A 0.456 g sample of an ore is analyzed for chromium

and found to contain 0.560 mg Cr2O3.

Express the concentration of Cr2O3 in the sample as

a) percent, %

b) parts per thousand, ppt

c) parts per million, ppm

 

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▶ 참고: %, ppm, ppb [ https://ywpop.tistory.com/2657 ]

 

 

 

(0.560 mg) (1 g / 1000 mg) = 0.000560 g Cr2O3

 

 

 

a) percent, %

(0.000560 g / 0.456 g) × 100 = 0.123%

 

 

 

b) parts per thousand, ppt

(0.000560 g / 0.456 g) × 1000 = 1.23 ppt

 

 

 

c) parts per million, ppm

(0.000560 g / 0.456 g) × 10^6 = 1.23×10^3 ppm