9.5 g of the tin (II) chloride. Convert into mega-moles

9.5 g of the tin (II) chloride. Convert into mega-moles

 

 

a) If the chemist is required to add 9.5 g of the tin (II) chloride to the solution,

determine the number of moles this equates to.

Watch your significant digits!

 

b) Convert your value from part “a” into mega-moles.

 

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a)

SnCl2의 몰질량 = 189.62 g/mol 이므로,

9.5 g / (189.62 g/mol) = 0.050 mol SnCl2

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

b)

0.050 = 5.0×10^(-2) mol 이고,

mega = 10^6 이므로,

5.0×10^(-8) mega-moles.

 

즉, 5.0×10^(-8) × 10^6 = 0.050