2PH3 → P2 + 3H2 Kp 398 873 K 0.412 atm 0.822 atm

2PH3 → P2 + 3H2 Kp 398 873 K 0.412 atm 0.822 atm

 

 

PH3는 높은 온도에서 P2와 H2로 분해된다.

2PH3(g) ⇌ P2(g) + 3H2(g) ... Kp = 398 at 873 K

873 K에서 PH3, P2, H2 혼합물이 평형에 있을 때,

P2 = 0.412 atm, H2 = 0.822 atm이다.

PH3는 얼마인가?

 

 

Phosphine (PH3) decomposes at elevated temperatures,

yielding gaseous P2 and H2:

2PH3(g) ⇌ P2(g) + 3H2(g) ... Kp = 398 at 873 K

 

 

When a mixture of PH3, P2, H2 comes to equilibrium at 873 K

according to the reaction 2PH3(g) ⇌ P2(g) + 3H2(g) ... Kp = 398 at 873 K,

where P_P2 = 0.412 atm and P_H2 = 0.822 atm. What is P_PH3?

 

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▶ 참고: 평형상수 식 [ https://ywpop.tistory.com/7136 ]

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Kp = (P_P2) (P_H2)^3 / (P_PH3)^2

 

 

 

398 = [(0.412) (0.822)^3] / (P_PH3)^2

 

(P_PH3)^2 = [(0.412) (0.822)^3] / 398

 

P_PH3 = [ [(0.412) (0.822)^3] / 398 ]^(1/2)

= 0.0240 atm

 

 

 

 

[키워드] PH3 기준문서, PH3의 분압 기준문서