H2C2O4 12.0 g 400.0 mL 25.0 mL 0.100 M KOH

H2C2O4 12.0 g 400.0 mL 25.0 mL 0.100 M KOH

 

 

이양성자산인 옥살산(H2C2O4) 12.0 g을 물에 녹여 400.0 mL 용액을 만들었다.

(1) 이 용액의 몰농도는?

(2) 이 용액 25.0 mL를 적정하는데 0.100 M KOH 용액이 몇 mL 필요한가?

H2C2O4(aq) + 2KOH(aq) → K2C2O4(aq) + 2H2O(l)

 

 

What is the molarity of a solution

made by dissolving 12.0 g of oxalic acid

in enough water to give 400.0 mL of solution?

How many mL of 0.100 M KOH would you need

to titrate 25.0 mL of the oxalic acid solution

according to the following equation?

H2C2O4(aq) + 2KOH(aq) → K2C2O4(aq) + 2H2O(l)

 

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> H2C2O4의 몰질량 = 90.0349 ≒ 90.03 g/mol

 

 

 

12.0 g / (90.03 g/mol) = 0.1333 mol H2C2O4

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

몰농도 = 0.1333 mol / (400.0/1000 L)

= 0.3333 M

( 참고 https://ywpop.tistory.com/3222 )

 

 

 

aMV = bM’V’

( 참고 https://ywpop.tistory.com/4689 )

 

(2) (0.3333 M) (25.0 mL) = (1) (0.100 M) (? mL)

? = [(2) (0.3333) (25.0)] / [(1) (0.100)] = 166.7 mL