1.5 L nitrogen gas 243.2 kPa room temperature

1.5 L nitrogen gas 243.2 kPa room temperature

 

 

A 1.5 L container has nitrogen gas

at a pressure of 243.2 kPa at room temperature.

How much of nitrogen is in the container in grams?

 

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1 atm = 101.324998 kPa 이므로,

243.2 kPa × (1 atm / 101.324998 kPa) = 2.400 atm

 

 

 

room temperature = 20℃

 

 

 

PV = nRT

( 참고 https://ywpop.tistory.com/3097 )

 

n = PV / RT

= [(2.400) (1.5)] / [(0.08206) (273.15+20)]

= 0.15 mol

 

 

 

N2의 몰질량 = 28 g/mol 이므로,

0.15 mol × (28 g/mol) = 4.2 g

 

 

 

답: 4.2 g