Find ΔH°_f of HCl(g) in kJ/mol

Find ΔH°_f of HCl(g) in kJ/mol

 

 

SO2Cl2(g) + 2H2O(l) → H2SO4(l) + 2HCl(g) ... ΔH° = -62 kJ

 

Find ΔH°_f of HCl(g) in kJ/mol.

SO2(g) ... ΔH°_f = -297 kJ/mol

SO3(g) ... ΔH°_f = -396 kJ/mol

SO2Cl2(g) ... ΔH°_f = -364 kJ/mol

H2SO4(l) ... ΔH°_f = -814 kJ/mol

H2O(l)... ΔH°_f = -286 kJ/mol

 

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ΔH°_rxn = [생성물들의 ΔH°_f 합] – [반응물들의 ΔH°_f 합]

( 식 설명 https://ywpop.tistory.com/3431 )

 

-62 = [(-814) + 2(x)] - [(-364) + 2(-286)]

-62 = (-814) + 2x - (–936)

2x = (-62) - (-814) + (–936) = -184

x = (-184) / 2 = -92

 

 

답: -92 kJ/mol