10 mg/L Ca(OH)2 용액의 pH

10 mg/L Ca(OH)2 용액의 pH

 

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Ca(OH)2의 몰질량 = 74.09 g/mol

0.010 g / (74.09 g/mol) = 0.000135 mol Ca(OH)2

0.000135 mol/L = 0.000135 M Ca(OH)2

 

 

Ca(OH)2(aq) → Ca^2+(aq) + 2OH^-(aq)

[OH^-] = 2 * 0.000135 = 0.00027 M OH^-

 

 

pOH = -log[OH^-] = -log(0.00027) = 3.57

pH = 14 – 3.57 = 10.43

 

 

답: 10.43

 

 

[ 관련 예제 https://ywpop.tistory.com/10613 ] 2000 mg/L Ca(OH)2 용액의 pH.