number of OH^- in 12.00 g Al(OH)3

number of OH^- in 12.00 g Al(OH)3

 

 

Determine the number of hydroxide ions in 12.00 g of aluminum hydroxide.

 

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> Al(OH)3의 몰질량 = 78.00 g/mol

> OH^-의 몰질량 = 17.01 g/mol

 

 

 

12.00 g Al(OH)3 × ((3×17.01 g OH^-) / 78.00 g Al(OH)3) × (1 mol OH^- / 17.01 g OH^-) × (6.022×10^23 개 / 1 mol)

= 12.00 × ((3×17.01) / 78.00) × (1 / 17.01) × (6.022×10^23)

= 2.779×10^23 개 OH^-